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Industrial Engineering Assignment

   

Added on  2021-04-16

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Industrial Engineering 1RESEARCH PAPER ON INDUSTRIAL ENGINEERINGA Research Paper on OEE ByStudent’s NameName of the ProfessorInstitutional AffiliationCity/StateYear/Month
Industrial Engineering Assignment_1

Industrial Engineering 2Question 1 TaskTimeImmediate predecessors A20-B18-C6AD10AE6BF7C,DG6E,FH14Ga.Solve using RPW with C = 30. Comment (quantitatively) on your solution quality.TaskTimeImmediate predecessors PWRPWA20-871B18-872C6A473D10A434E6B335F7C,D276G6E,F208H14G149Predecessors DiagramStationTime remainingTasksTime used130, 10A20230, 18, 6B, C, 24330, 20, 14, 7, 1D, E, F, G29430, 14H16LB = Summation of ti/c = 87/30 = 2.9LE = Summation of ti/kc = 87/(4*30) = 0.725SI = {(30-20)2 + (30-24)2 + (30-29)2 + (30-16)2}1/2
Industrial Engineering Assignment_2

Industrial Engineering 3SI = {(10)2 + (6)2 + (1)2 + (14)2}1/2SI = {100+36+1+196}1/2SI = 3331/2SI = 18.25Approaches of Processing Time RandomnessDepending of the properties of the samples, there are numerous approaches of addressing time randomness, these approaches include branching approach, renewal approach, Gaussian approach, Levy approach, Markov approach, martingales, and random walks[ CITATION Sac12 \l 2057 ]. b)Solve using RPW, with considering variation. Treat the task times as normally distributed with a coefficient of variation equal 0.2. Assume that 95% of the time all tasks must be completed. Comment on other approaches to address processing time randomness.Coefficient variation = 0.2Task completed = 95%Actual time = previous time*coefficient of variationTime (Task 1) = 20*0.2 = 4By taking into consideration the coefficient of variation of 0.2 and 95% task completion, the fallowing table of RPW can be gotten:TaskTimeImmediate predecessors PWRPWA4-17.41B3.6-17.42C1.2A9.43D2A8.64E1.2B6.65
Industrial Engineering Assignment_3

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