This document provides solutions and explanations for various questions related to inventory control system. It covers topics such as batch size, expected profit, reorder level, safety stock, and more. The solutions are provided in a step-by-step manner, making it easy to understand and implement.
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Inventory control system [Document subtitle] [DATE]
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Question 1 Number of batches = 100 Costs of cutting = $14 Sell price = $30 Number of trees that should be cut down by the company =? Expected profit =? Assuming zero salvage value and hence, Shortage cost = sell price – Cost of cutting = 30-14= $16 Overstocking cost = Cost of cutting – Salvage value = $14 – 0 = $14 Now, Critical ratio = Shortage cost / (Shortage cost + Overstocking cost) = 16 / (16+14) = 0.53 Probability distribution It can be seen based on the above table that the critical ratio falls at the cumulative probability of 0.62 which means the corresponding batches would be 5. Thereby, the total number trees = 5 Hence, it can be concluded that optimal number of trees that should be cut would be 5 trees. 1
Average demand = 4.83 Expected shortage = 0.71 Now, Expected Sales = (Avg. demand) – (Exp. Sales) = 4.83 – 0.71 = 4.12 Expected overage =5 – 4.22 = 0.88 Expected revenue = {(Sell price * Expected sales) + (Expected overage* Salvage value)} * Total batches = {(30*4.12) + (0.88*0)} * 100 = 12360 Expected cost = Cost of cutting * Optimal number of trees * Total batches = 14 *5*100 = 7000 Expected profit = Expected revenue – Expected cost = 12360 – 7000 = $5360 Therefore, the company would get an expected profit of $5360. 2
Question 2 D = 12.5 R = $65 S = $170 H = $7 L= 1 Optimal Value of Order Quantity¿(2∗D∗S H) 0.5 OptimalValueofOrderQuantity=(2∗12.5∗170 7)0.5 =24.64∨25 Reorder Level = DL = 12.5 * 1 = 12.5 Question 3 Service level = 95% Mean demand of the company = 280 units a week Standard deviation = 38 units lead time = 2.2 weeks (Constant) Company’s practice for this item would constitute the ROP and safety stock. Safety Stock Safetystock=Z∗standarddeviation∗(Leadtime)0.5 zvaluefor95%servicelevel=1.65 Safetystock=1.65∗38∗(2.2)0.5=92.9∨93 ROP 3
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ROP=(Mean∗Leadtime)+¿ ROP=(280∗2.2)+(1.65∗38∗(2.2)0.5)=708.9∨709 Company’s practice for this item would constitute 709 ROP and 93 safety stock. Now, the annual cost associated with this scenario is shown below. = {(100*280)+(709-280)*400 }/52 = $3838.46 Company’s practice for this item would constitute the ROP and safety stock when service level is 98%. Safety Stock Safetystock=Z∗standarddeviation∗(Leadtime)0.5 zvaluefor98%servicelevel=2.055 Safetystock=2.055∗38∗(2.2)0.5=115.8∨116 ROP ROP=(Mean∗Leadtime)+¿ ROP=(280∗2.2)+(1.65∗38∗(2.2)0.5)=731.82∨732 Company’s practice for this item would constitute 732 ROP and 116 safety stock when the service level has increased to 98% from 95%. Question 4 Given data and information is shown below. Selling price per unit = $40 4
Total number sold (from above column) = 118 +84+96 +135 +102 +66 = 601 Revenue = Total number sold * Selling price per unit = 601 *40 = $24,040 The main objective is to find the profit and profit margin that is a function of the respective inventory method used for determining the cost of inventory. Method 1: FIFO In this method, the inventory which has been bought first would be sold by the company at first. Closing stock value = 69*32 = $2208 Cost of goods sold = 3304 +1324+2728+3831+2789+1892 = 15,868 Profit = Revenue - Cost of goods sold = 24,040 – 15868 = $8172 ProfitMargin(%)=(Profit Revenue)∗100=(8172 24040)∗100=33.99% Method 2: LIFO In this method, the inventory which has been bought first would be sold by the company at last. 5
Closing stock value = (12*28) +(26*26) +(17*30) +(14*32) =$1970 Cost of goods sold = 3304 + 2184 +2880 +3645+ 2865 +2112 = $14,125 Profit = Revenue - Cost of goods sold = 24,040 – 14125 = $9915 ProfitMargin(%)=(Profit Revenue)∗100=(9915 24040)∗100=41.24% Method 2: WACC In this method, the inventory which has been bought would be sold by the company at the respective weighted average cost in relation to the sale only. Closing stock value = 69*30.31 =$2091.39 Cost of goods sold = 3304 + 2200.53+2792.20+3731.41+2840.33+2000.3 = $16,868.7 Profit = Revenue - Cost of goods sold = 24,040 – 16868.7 = $7171.23 ProfitMargin(%)=(Profit Revenue)∗100=(7171.23 24040)∗100=29.83% Question 5 (a)The relevant scatter plot between Sales and year is shown below. 6
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Correlation coefficient has been determined through CORREL function of excel. Correlation coefficient0.868 A positive linear relationship has been observed from the scatter plot. The correlation coefficient comes out to be 0.868 which indicates that variables are strongly correlated with the positive relationship. Further, it can be seen from the above shown scatter plot that some of the points do not fall on the line of best fit which implies that regression model needs to be made in order to determine the relationship between the variables. Regression output for the least square point estimates 7
Least square regression line Y=a+bx+e Sales = -9702.85 + (4.90 * Year) + 10.5804 (b)The relevant scatter plot between Sales and market is shown below. 8
CorrelationcoefficienthasbeendeterminedthroughCORREL function of excel. Correlation coefficient0.661 A positive linear relationship has been observed from the scatter plot between the variables. The correlation coefficient comes out to be 0.661 which indicates that variables are positively moderately correlated. Further, it can be seen from the above shown scatter plot that some of the points do not fall on the line of best fit which implies that regression model needs to be made in order to determine the relationship between the variables. Regression output for the least square point estimates 9
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Least square regression line Y=a+bx+e Sales = 53.44 + (0.91 * Market) + 16.016 (c)The most appropriate model would be the first one where the dependent variable is sales and independent variable is year. This is because the R square value comes out to be higher for model one. Also, the sales seem to follows a linearity with respect to the year and thus, the sales would be best explained through year rather than market and thus, it would be preferable model. 10