Questions and Answers on IP Addressing and Subnetting

Running Head: QUESTIONS & ANSWERS
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QUESTIONS AND ANSWERS
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QUESTIONS & ANSWERS
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1) IP Addressing
a) Classical IP addressing provided three address classes for assigning to network
devices (hosts). How can you determine which class an IP address class by
checking its first octet?
In IP addressing technology, ranges of IP addresses have been classified into classes A-C.
These classes are differentiated by the last octet. For class A the octet range is 1-126, for B its
128 – 191 and for Class C is 192 – 223 (Golan, Rivner, Tsur, Orad, & Bennett, 2015).
b) Windows and other operating systems allow a host to have multiple IP addresses.
What is the function of multiple IP addresses in a host? Will this have any
consequences for the ARP protocol? 1 Mark
Mainly, multiple IP addressing has several functions. For instance, if someone needs to
host many SSL sites, using multiple IP addresses helps him do it much easier. Secondly, an IP
address of a host may be mistakenly blacklisted as a SPAM, (Stolorz et al, 2015). Using multiple
IP addresses makes one escape being blacklisted as a SPAM. Additionally, multiple IP addresses
allow same service to be run multiple times (Shang, Droms, & Zhang, (2016).
Multiple IP addressing does not have any consequences to ARP protocol.
2) Subnetting
a) you are provided with the address range 192.168.10.0/24. Create a sub-networking
scheme that provides six networks.

QUESTIONS & ANSWERS
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Address 192.168.10.0 = 11000000.10101000.00001010.00000000
Default class C Subnet = 255.255.255.0 = 11111111.11111111.11111111.00000000
The formula (2^x)-2 >= subnets is used in the calculation of required bits.
(2^3)-2 =6 (the number of requested networks)
The subnet mask has been created using 3 bits => 128+64+32 = 224.
224 in binary form can be written as = 11111111.11111111.11111111.11100000
The sub-networks are therefore listed below by replacing the first three digits in the last octet.
Subnet 0 = 11000000.10101000.00001010.00000000 = 192.168.10.0
Subnet 1 = 11000000.10101000.00001010.00100000 = 192.168.10.32
Subnet 2 = 11000000.10101000.00001010.00100000 = 192.168.10.62
Subnet 3 = 11000000.10101000.00001010.01100000 = 192.168. 10.96
Subnet 4 = 11000000.10101000.00001010.10000000 = 192.168. 10.128
Subnet 5 = 11000000.10101000.00001010.10100000 = 192.168. 10.160
Subnet 6 = 11000000.10101000.00001010.11000000 = 192.168. 10.192
Subnet 7 = 11000000.10101000.00001010.11100000 = 192.168. 10.224
b) What subnetting alternatives exist for providing a network address for a point?to?point
link?
In point to point network addressing, two approaches are used: numbered and
unnumbered connection (Vardy, 2016). In the numbered connection approach, a unique IP