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ME405: Thermal Systems Design Assignment

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Thermal Systems Design (ME405)

   

Added on  2020-03-16

ME405: Thermal Systems Design Assignment

   

Thermal Systems Design (ME405)

   Added on 2020-03-16

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ME405: Thermal Systems DesignWashington State University Project 1 (Final Report Due: October 9, 2017)Solution Given:Steam turbine power plant is working on steam reheat – regenerative co-generation for theconsumption of electricity and water.Maximum demand- 20MWVolume of hot water demand weekdays - 850,000gallons = 3217.60002m3Design constraintsThe thermal efficiency of the system should be higher than 45%Combustion efficiency = 88%All the pumping energy should come from the turbine work.Temperature of the hot water = 185°FTurbine isentropic efficiency = 93%AnswersPart aThe system block of the steam turbine power plant are given below
ME405: Thermal Systems Design Assignment_1
Figure 1: System diagram The T-s diagram of the system are given below-Figure 2: T-s diagramPart bThe basic analysis of the system are given below-
ME405: Thermal Systems Design Assignment_2
workdonebypump1+pump2=v8(P9P8)+v8(P10P7)= 3217.60002m3kg(70005)+ 3217.60002m3kg(5900110)106+ 15MW= 51.13 MWFor the given temperature and pressure, the value of the specific enthalpies are given below-h1=h2=h3=h4=3009.31KJkgBased on the values obtained from steam tableh4=3423.34KJkgh5=3434.34KJkgh6=3447.34KJkgh7=hf@500KPa=645.34KJkgh8=hf@5KPa=122.17KJkgh9=h8+Wpump1=129.45KJkgh10=h8+Wpump2=45.17KJkgW turbine 1 = 3217.60002m3kg(1233.21211.0)106= 71.430MWW turbine 2 = 3217.60002m3kg(645.34122.17)106= 16.83MWW turbine 3 = 3217.60002m3kg(129.4545.17)106
ME405: Thermal Systems Design Assignment_3

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