Calculations Temperature of cold water PDF

NAME:
EXPERIMENT 8: PARTNER:
DATE:
REPORT SHEET
1. HEAT CAPACITY OF CALORIMETER
Calculations
Temperature of cold water 6.5 oC
Temperature of warm water 42.9 oC
Maximum temperature reached 33.5 oC
T (cold water)* 33.5-6.5 27oC
T (hot water)* 33.5-42.9 -9.4°C
Heat lost by warm water Mass x change in temperature
x specific heat capacity of
water
=(50ml)x(1g/cm3)x4.184x-9.4
-1966.48J
Heat gained by cold water Mass x change in temperature
x specific heat capacity of
water
=(50ml)x(1g/cm3)x4.184x27
5648.4J
Heat gained by calorimeter q(warm)+q(cold)
+q(calorimeter)=0
q(calorimeter)=0-(5648.4-
1966.48)
-3681.92J
Heat capacity of calorimeter Heat gained by the
calorimeter/change in
calorimeter temperature -136.37
j/°c

=-3681.92/27
* Remember, T = final temperature – initial temperature

2. NEUTRALIZATION OF HCl (aq) AND NaOH (aq)
Calculations
Initial temperature NaOH 21.2 oC
Final temperature of mixture 27.7 oC
Change in temperature 27.7-21.2 6.5 oC
qsolution Mass x change in
temperature x specific heat
capacity of water
=100mlx1.02g/
mlx6.5°cx4.02joule/gram/°c
2665.26J
qcalorimeter Change in temperature x
heat capacity of calorimeter
=6.5x-136.37
-886.405J
qreaction qsolution + qcalorimeter + qreaction=0
qreaction =0-(2665.26+-
886.405)
-1778.86J
Enthalpy of Neutralization
(per mole water formed)
-1778.86/0.05moles
=-35577.1j/mol
Then divide by 1000 to
convert to kilojoules
-35.58kJ/mol
3. HEAT OF SOLUTION OF NaOH(s)
Calculations
Mass of NaOH used 2.20 g
Initial temperature water 18.9 oC
Highest temperature reached 28.5 oC
Change in temperature 28.5-18.9 9.6 oC
qsolution Mass x change in
temperature x specific heat