Question 1 Mean = 114.8 mm Hg Standard Deviation = 13.1 mm Hg

Question 1
Mean = 114.8 mm Hg
Standard Deviation = 13.1 mm Hg
Sample size = 4
X = 140 mm Hg
Z = (140-114.8)/(13.1/40.5)= 3.847
P (Z<3.847) = 0.99994
Requisite probability = (1-0.99994) =0.0001 (Option D)
Question 2
Standard error = Standard deviation /Sample size 0.5 = 25/(300.5)= 4.56 (Option C)
Question 3
Considering that population standard deviation is not known, hence the t critical value needs to
be determined with 95% confidence and degrees of freedom as (30-1) =29. Further, two tail
value would be used for confidence interval. This value comes out as 2.045 (Option E).
Question 4
Margin of error = 4.56*2,045 = 9.33 (Option D)
Question 5
Confidence Interval = 140+/- 9.33 = (131.149)
Hence, both c and d are correct (Option F)
Question 6
The claim to be tested is shown as alternative hypothesis. Also, population mean is denoted by μ.