If the number is positive, it remains the same. If not, it is converted to 1. The final number is displayed.

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05 Aug 2021

Re-type the code and fix any errors. The code should convert non-positive numbers to 1. if (userNum > 0) cout << "Positive." << endl; else cout << "Not positive, converting to 1." << endl; userNum = 1; cout << "Final: " << userNum << endl;

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05 Aug 2021

In the above code, we need to use the opening and closing brackets for if and else statement block. Logic and other statements of the code are correct...

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Re-type the code and fix any errors. ...

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