Biostatistics for Healthcare Research

Running head: BIOSTATISTICS FOR HEALTHCARE RESEARCH
BIOSTATISTICS FOR HEALTHCARE RESEARCH
Name of the Student
Name of the University
Author note

BIOSTATISTICS FOR HEALTHCARE RESEARCH1
Question 1.
Step 1: Specify the hypotheses (symbolically)
Null Hypothesis: μ = 55
Alternative hypothesis: μ ≠ 55
α = 0.05 (two-tailed)
S= √ ∑ ( X- X )2
(n-1 ) = √ 148 .90
9 =4 . 07
t=X −μ
SEM
S x=s
√ n =4 . 07
3 . 16 =1. 29
t c =(9 . 90−6 .75 )
1. 29 =2 . 44
t α =2 .262
2. 44>2 .262
Step 2: Calculate the necessary statistics
SEM = SD /√ (n)
=8 /√ 64
= 1
t = (57-55)/1=2
Step 3: Establish the critical value and region of rejection. (Drawing the picture helps
you understand the process)
Degree of freedom or Df=N-1=64-1=63
Alpha values is α = 0.05
For the critical value can be found for Df of 63 and α = 0.05 in the following two tail
distribution table

BIOSTATISTICS FOR HEALTHCARE RESEARCH2
The two tail distribution table:
DF A = 0.2 0.10 0.05 0.02 0.01 0.002 0.001
∞ ta = 1.282 1.645 1.960 2.326 2.576 3.091 3.291
1 3.078 6.314 12.706 31.821 63.656 318.289 636.578
2 1.886 2.920 4.303 6.965 9.925 22.328 31.600
3 1.638 2.353 3.182 4.541 5.841 10.214 12.924
4 1.533 2.132 2.776 3.747 4.604 7.173 8.610
5 1.476 2.015 2.571 3.365 4.032 5.894 6.869
6 1.440 1.943 2.447 3.143 3.707 5.208 5.959
7 1.415 1.895 2.365 2.998 3.499 4.785 5.408
8 1.397 1.860 2.306 2.896 3.355 4.501 5.041
9 1.383 1.833 2.262 2.821 3.250 4.297 4.781
10 1.372 1.812 2.228 2.764 3.169 4.144 4.587
11 1.363 1.796 2.201 2.718 3.106 4.025 4.437
12 1.356 1.782 2.179 2.681 3.055 3.930 4.318
13 1.350 1.771 2.160 2.650 3.012 3.852 4.221
14 1.345 1.761 2.145 2.624 2.977 3.787 4.140
15 1.341 1.753 2.131 2.602 2.947 3.733 4.073
16 1.337 1.746 2.120 2.583 2.921 3.686 4.015
17 1.333 1.740 2.110 2.567 2.898 3.646 3.965
18 1.330 1.734 2.101 2.552 2.878 3.610 3.922
19 1.328 1.729 2.093 2.539 2.861 3.579 3.883
20 1.325 1.725 2.086 2.528 2.845 3.552 3.850