logo

Model 1 Call: lm(formula = age ~ proportion.black) Residuals:

Assess the relationship between the degree of black pigmentation of a male lion’s nose and its age in order to predict a lion’s age from its nose.

2 Pages151 Words260 Views
   

Added on  2023-04-07

Model 1 Call: lm(formula = age ~ proportion.black) Residuals:

Assess the relationship between the degree of black pigmentation of a male lion’s nose and its age in order to predict a lion’s age from its nose.

   Added on 2023-04-07

ShareRelated Documents
Model 1
Call:
lm(formula = age ~ proportion.black)
Residuals:
Min 1Q Median 3Q Max
-2.5449 -1.1117 -0.5285 0.9635 4.3421
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 0.8790 0.5688 1.545 0.133
proportion.black 10.6471 1.5095 7.053 7.68e-08 ***
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 1.669 on 30 degrees of freedom
Multiple R-squared: 0.6238, Adjusted R-squared: 0.6113
F-statistic: 49.75 on 1 and 30 DF, p-value: 7.677e-08
Model 2
Call:
lm(formula = `log(age)` ~ `log(proportion.black)`)
Residuals:
Model 1 Call: lm(formula = age ~ proportion.black) Residuals:_1

End of preview

Want to access all the pages? Upload your documents or become a member.

Related Documents
Model parameter are tested for statistical
|14
|3949
|14

Frequency Analysis of Regenerate Vegetative or by Seed and Cross-Classified Plant Species
|9
|1580
|251

Research on Microorganisms | Study
|16
|2055
|294

Data Analysis Project for Desklib
|9
|2087
|218

Data Analysis: Assignment
|16
|2057
|325

Linear Regression and Correlation Analysis Assignment
|13
|1372
|109