Signal System Tasks Question 2022

SIGNAL SYSTEM 0
Signal System

SIGNAL SYSTEM 1
Task 2
Question 1
a. Sin33t/t+ sin2t
By changing the above equation we can find sapling interval which is given
below:
[3*(sin3t+ sin3t)/4t]+ sin2t
In which, Wmax= 9
Or, 2π *Fmax= 9
Fmax= 9/2π........................................... (1)
We now that, Fs= fmin
Or, Fs= 2Fmax (Schneider 5-10).
So, Fs= 2(9/2π)= 9/π........................ (2)
Therefore, Ts= 1/Fs
Ts= π/9
b. Sin33t/t4 + sin2t
As per the above calculation we can find sampling interval in which Wnr is ∞
which will be helpful for solving the question.
Wnr = max(∞, 4)
Or, Wnr= ∞
Therefore, Ts = 0
c. (Sin33t/t2)* sin2t

SIGNAL SYSTEM 2
It is determined that two input signals convolve with least frequency signal
so, the minimum frequency will be considered in this situation.
So, Wmax= 2
Wmax= 2π *Fmax= 2
Fmax= 1/π
Fmin= 2Fmax= 2/π
Or, Ts= π/2
d. (Sin3t/t)* Sin22t
(Sin3t/t)* (1-cos2t/2)
Here, Wmax= 3
Fmax= 3/2π
Fin= 2(3/2π)= 3/π
Therefore, Ts= π/3
Question 2
It is determined that the applied frequency is 10 KHz and discrete time
transfer function is given below:
HDT (Z)= 0.05/z(z-0.95)
Here sampling time= 1/10= 0.1 ms
We now that, Z= est
Z= est/2/e-st/2 (Leube, Katharina and Siegfried 5-9)
Or, Z= (1+ st/2)/(1-st/2)
Z= (1+0.05ms)/ (1-0.05ms)