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Trigonometry, Geometry and Linear Equation - Learning Activity 25-27

   

Added on  2023-06-10

14 Pages1133 Words461 Views

LEARNING ACTIVITY 25 - PERIMETER
1.
Perimeter of a square = 4* side
Therefore,
perimeter= 4*40 cm
= 160 cm
2.
Perimeter of a rectangle= 2 (length+ breadth)
Length= 60 cm
Breadth= 30 cm
Perimeter= 2 (60+30)
= 2* 90
= 180 cm
3.
Side= 35 cm
Perimeter of equilatral triangle = 3*side
= 3*35
= 105 cm
4.
Perimeter = sum of all four sides
= 20+30+25+24
= 99 cm
1

5.
Perimeter= sum of all 5 sides
=40+20+22+40+31
= 153 cm
6.
Circumference of a circle = π x diameter
d = 7.9 cm
circumference = π x 7.9
= 3.14* 7.9
= 24.806 cm
7.
Circumference of a circle = π x diameter
d = 6.3 cm
circumference = π * 6.3
= 3.14 * 6.3
= 19.782 cm
8.
Circumference of a circle= 2 π r
r = 7.3
circumference = 2 * π* r
= 2* 3.14* 7.3
= 45.844 cm
9.
2

Circumference of a circle= 2 π r
r = 7.6 cm
circumference = 2 * π* r
= 2* π* 7.6
= 47.728 cm
10.
Perimeter = perimeter of rectangle- 10 + sum of 2 sides of right triangle
= 2 (length+breadth) – 10 + sum of 2 sides of right triangle
= 2 (22+7) – 10 + (7.5 +12.5)
= 2 (29) – 10 + 20
= 58 – 10 + 20
= 68m
11.
Perimeter = perimeter of rectangle – diameter + ½ circumference
= 2 (length+breadth) – 4.1 + ½ π d
Where d= diameter
= 2 (11.1+5.1) – 4.1 + ½ πd
=2 (16.2) – 4.1 + 0.5 * 3.14 * 4.1
= 32.4 – 4.1 + 6.437
= 38.837- 4.1
= 34.737 km
3

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