Calculation of Water Flow Rate in a System using Bernoulli's Equation

Determine the volume flow rate of water (T = 40oC) flowing in the system below in (m3/min).
The information provided is as follows
Temperature = 400 C
Diameter of the smaller pipe = 4 in
Diameter of the larger pipe = 16 in
The length of the smaller pipe = 43 m
The length of the larger pipe = 25 m
Bernoulli’s equation states that
P 1
eg + V 12
2 g + Z 1 = constant
P 1
eg + V 12
2 g + Z1 = P 2
eg + V 22
2 g + Z2
0 + 0 + 15 = 0 + 0 +0
∑ hL = 15 m
For ductile pipe
Pipe roughness size = 0.15 mm
From equation of continuity
A1V1 = A2V2
V2 = A1/A2*V1
V2= 0.444V1
Major loss
Pipe 1

f 1 ( L1
D 1 ) ( V 2 1
2 g )
f*
43
0.1016 ∗v2
2 g
= 21.5713fV2
Pipe 2
f 2 ( L2
D 2 ) ( V 2 2
2 g )
f*
25
0.1016 ∗(0.444 V 1)2
2 g
= 2.4724fV12
Total major loss = 21.5713fV2 + 2.4724fV12 = 24.0437fV21
Minor loss
1. At the Entry
hentry = Kentry* v2 1
2 g
pipe 1
at sharp entry
Kentry = 0.5
hentry = 0.5* v2
2 g = 0.0255V21
Pipe 2