HI6007 : Statistics And Research Methods For Business
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Holmes Institute Sydney
Statistics And Research Methods For Business (HI6007)
Added on 2020-05-16
HI6007 : Statistics And Research Methods For Business
Holmes Institute Sydney
Statistics And Research Methods For Business (HI6007)
Added on 2020-05-16
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Running head: STATISTICSStatisticsName of the student:Name of the university:Author’s note:
1STATISTICSTable of ContentsAnswer 1..........................................................................................................................................2Part a............................................................................................................................................2Part b............................................................................................................................................2Part c............................................................................................................................................2Answer 2..........................................................................................................................................2Answer 3..........................................................................................................................................3Part a............................................................................................................................................3Part b............................................................................................................................................3Answer 4..........................................................................................................................................4Answer 5..........................................................................................................................................4Answer 6..........................................................................................................................................4Part a............................................................................................................................................4Part b............................................................................................................................................4Part c............................................................................................................................................5Answer 7..........................................................................................................................................5Answer 8..........................................................................................................................................5Part a............................................................................................................................................5Part b............................................................................................................................................6Part c............................................................................................................................................6Answer 9..........................................................................................................................................6Part a............................................................................................................................................6Part b............................................................................................................................................6Part c............................................................................................................................................7Answer 10........................................................................................................................................7Part a............................................................................................................................................7Part b............................................................................................................................................7Part c............................................................................................................................................7Part d............................................................................................................................................7
2STATISTICSAnswer 1Part aSource ofVariationSum of squaresDegrees ofFreedomMean SquareFBetweentreatments903¿903=30¿306=5Withintreatments(Error)12020¿12020=6Total= (90 + 120)= 210= (3+20)=23Table 1: ANOVA tableThe F-statistic is calculated as 5. The p-value for the F-statistic with 3 and 20 degreesof freedom is found to be 0.00951034. At 1% level of significance (α=0.01), as calculated p-value is less than 0.01, we decide to reject the null hypothesis.Part b Total number of groups = (degrees of freedom of between treatments) + 1 = (3+1) = 4Hence, there are 4 groups in the question.Part c Total number of observations = (degrees of freedom of within treatment) + 1= (20+1) = 21There are 21 observations in the question.Answer 2Linear regression model:CoefficientsStandardErrort StatP-valueLower95%Upper95%Intercept13613.769.8810.000104.2621167.7379Year (t)39.182.2217.6640.00034.066844.29684Table 2: Linear Regression ModelThe simple linear regression, Y = a + b*X.Here, the intercept (a) = 136, the slope (b) = 39.18.According to the table 2, the estimated number of units sold by the auto manufactureris: Number of Units sold (‘000s) = 136 + 39.18*YearIt is the linear model of this analysis.
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