Statistics: Hypothesis Testing, Correlation, Regression

Statistics
Statistics
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Statistics
QUESTION 1
Direct Indirect Total
Male 5 10 15
Female 25 10 35
Total 30 20 50
Table 1
a. It is a two tailed test
b. Dependent variable: Choice
c. Independent variable: Sex
d. Hypothesis
H0: Sex and the choice of direct versus indirect social work practice are independent.
H1: Sex and the choice of direct versus indirect social work practice are not independent
e. Degrees of freedom ( r −1 ) ( c−1 )= ( 2−1 ) ( 2−1 )=1
Er ,c= ( nr ×nc ) /n
E1,1 =15 ×30
50 =9
E1,2 =15 ×20
50 =6
E2,1 =35 ×30
50 =21
E2,2 =35 × 20
50 =14
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Statistics
X2 =∑ [ ( nr ,c−Er , c )2 / Er ,c ]
X2 = ( 5−9 ) 2
9 + ( 10−6 ) 2
6 + ( 25−21 ) 2
21 + ( 10−14 ) 2
14
X2 =1.78+2.67+0.76+1.14=6.35
Using chi-square distribution calculator to find p-value we get;
P ( X2 >6.35 ) =0.01
Since P-value (0.01) is less than the significance level (0.05), we reject the null hypothesis. We
conclude therefore that sex and the choice of direct versus indirect social work practice are not
independent.
QUESTION 2
a. It is a one tailed test
b. Independent variable: Group work
c. Dependent variable: Standardized assertiveness scale.
d. Null hypothesis
H0: There is no significant difference between the mean assertiveness scale score for group work
and individual work.
H1: Mean assertiveness scale score for group work greater than mean assertiveness scale score
for individual work.
Paired sample t-test was employed and the results are as shown below;
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